4sin^2x-5sinx+2cos^2x=0

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Solution for 4sin^2x-5sinx+2cos^2x=0 equation: 


Simplifying
4sin2x + -5sinx + 2cos2x = 0

Reorder the terms:
2cos2x + -5insx + 4in2sx = 0

Solving
2cos2x + -5insx + 4in2sx = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '5insx' to each side of the equation.
2cos2x + -5insx + 5insx + 4in2sx = 0 + 5insx

Combine like terms: -5insx + 5insx = 0
2cos2x + 0 + 4in2sx = 0 + 5insx
2cos2x + 4in2sx = 0 + 5insx
Remove the zero:
2cos2x + 4in2sx = 5insx

Add '-4in2sx' to each side of the equation.
2cos2x + 4in2sx + -4in2sx = 5insx + -4in2sx

Combine like terms: 4in2sx + -4in2sx = 0
2cos2x + 0 = 5insx + -4in2sx
2cos2x = 5insx + -4in2sx

Divide each side by '2os2x'.
c = 2.5ino-1s-1 + -2in2o-1s-1

Simplifying
c = 2.5ino-1s-1 + -2in2o-1s-1

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